使用shell脚本判断文件后缀的方法实例_linux shell_

#!/bin/bash # --------------------------------------------------------------------------- # # 获取文件名后缀 # Parameter1: 文件名 # output: Yes # return: None # --------------------------------------------------------------------------- # function FileSuffix() { local filename="$1" if [ -n "$filename" ]; then echo "${filename##*.}" fi } # --------------------------------------------------------------------------- # # 获取文件名前缀 # Parameter1: 文件名 # output: Yes # return: None # --------------------------------------------------------------------------- # function FilePrefix() { local filename="$1" if [ -n "$filename" ]; then echo "${filename%.*}" fi } 

# --------------------------------------------------------------------------- # # 判断文件后缀是否是指定后缀 # Parameter1: 文件名 # parameter2: 后缀名 # output: None # return: 0: 表示文件后缀是指定后缀；1: 表示文件后缀不是指定后缀 # --------------------------------------------------------------------------- # function IsSuffix() { local filename="$1" local suffix="$2" if [ "$(FileSuffix ${filename})" = "$suffix" ]; then return 0 else return 1 fi } file="demo.txt" IsSuffix ${file} "txt" ret=$? if [ $ret -eq 0 ]; then echo "the suffix of the ${file} is txt" fi

file=$1 if [ "${file##*.}"x = "css"x ]||[ "${file##*.}"x = "js"x ];then     do something fi

for n in `find . -name "*.py" -o -name "*.sh" -o -name "*.css" -o -name "*.js" -o -name "*.html"`; do    something done